(编辑:jimmy 日期: 2024/12/24 浏览:2)
本文实例为大家分享了vue实现移动端返回顶部的具体代码,供大家参考,具体内容如下
HTML:
<template> <div class="home"> <div v-for="ys in 100" :key="ys"> <p>1</p> </div> <div @click="back" class="back1" v-show="isShow">▲</div> </div> </template>
JS:
<script> export default { data() { return { isShow: true }; }, handleScroll() {// handleScroll 和 methods 是同级 if (window.pageYOffset > 300) { //window.pageYOffset:获取滚动距离 this.isShow = true; } else { this.isShow = false; } // console.log(window.pageYOffset); }, methods: { //点击事件: back() { //返回顶部 $这个地方需要引入在线jq //<script src="/UploadFiles/2021-04-02/jquery.min.js">CSS:
<style scoped> .back1 { width: 50px; height: 50px; background: #eee; position: fixed; right: 5px; bottom: 50px; z-index: 1000; text-align: center; line-height: 50px; } </style>之前小编看到的一篇文章分享给大家:Vue实现返回顶部按钮
<template> <div class="scrollTop"> <div class="backTop" @click="backTop"> <button v-show="flag_scroll"> 返回顶部 </button> </div> //数据源 <div></div> </div> </template> <script> export default { name: 'scrollTop', data() { return { flag_scroll: false, scroll: 0, } }, computed: {}, methods: { //返回顶部事件 backTop() { document.getElementsByClassName('scrollTop')[0].scrollTop = 0 }, //滑动超过200时显示按钮 handleScroll() { let scrollTop = document.getElementsByClassName('scrollTop')[0] .scrollTop console.log(scrollTop) if (scrollTop > 200) { this.flag_scroll = true } else { this.flag_scroll = false } }, }, mounted() { window.addEventListener('scroll', this.handleScroll, true) }, created() { }, } </script> <style scoped> .scrollTop{ width: 100%; height: 100vh; overflow-y: scroll; } .backTop { position: fixed; bottom: 50px; z-index: 100; right: 0; background: white; } </style>以上就是本文的全部内容,希望对大家的学习有所帮助,也希望大家多多支持。